COURSE MATH 3191-004: Applied Linear Algebra. Fall 1994. University of Colorado Denver INSTRUCTOR Dr. Andrew Knyazev Office: CU (Dravo) 620G. Phone: 556-8102. Office hours: Tue 3pm - 6pm EXAM #3 (Chapter 5) 15% of the FINAL GRADE Monday, November 14 2 0 0 2 Let A be the following matrix 1 1 0 1 for problems 1-7. 1 2 2 1 2 0 0 1 1. rank(A) = [A] 1 [B] 2 [C] 3 [D] 4 2. Which of the following is a vector in the nullspace of A? [A] (0 0 0 0) [B] (0 1 0 0) [C] (0 -1 2 0) [D] The correct answer is not given by [A],[B], or [C] 3. The linear system Ax=b is not consistent for b= [A] (0 0 0 0) [B] (0 1 0 0) [C] (0 -1 2 0) [D] The correct answer is not given by [A],[B], or [C] 4. rank(A) - nullity(A) = [A] 1 [B] 2 [C] 3 [D] 4 5. The dimension of the subspace spanned by a first 3 rows of A equals [A] 1 [B] 2 [C] 3 [D] 4 6. Which of the following statements must be true: [A] The last row of A can be expressed as a linear combination of the first 3. [B] The last column of A can be expressed as a linear combination of the first 3. [C] Both [A] and [B] are correct statements [D] None of the above is correct 7. Let 4x8 matrix B = [A A]. Then nullity(B) = [A] 1 [B] 2 [C] 3 [D] 4 8. Let u, v and w be vectors in 10 dimensional vector space. Then dim(span{u,v,w}) can not be equal to [A] 1 [B] 2 [C] 3 [D] 4 9. Let A, B, C, and D be the following 2x2 matrices. 2 0 1 1 1 2 2 0 0 2 0 1 2 1 0 1 We consider A, B, C, and D as elements of the vector space of all 2x2 matrices with real entries. Then [A] D can be expressed as a linear combination of A, B, and C. [B] A, B, C, and D form a basis [C] Both [A] and [B] are correct statements [D] None of the above is correct 10. Let p(x) = 2x + 2, q(x) = x + x + 1, r(x) = x + 2x + 2x + 1, and t(x) = 2x + 1. We consider p(x), q(x), r(x), and t(x) as elements of the vector space of all real-valued functions defined on the entire real line. Then [A] t(x) can be expressed as a linear combination of p(x), q(x), and r(x). [B] p(x), q(x), r(x), and t(x) form a basis [C] Both [A] and [B] are correct statements [D] None of the above is correct